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Re: [Xen-devel] [RFC][PATCH 0/5] Add V4V to Xen



On 28 June 2012 14:47, Ian Campbell <Ian.Campbell@xxxxxxxxxx> wrote:
> On Thu, 2012-06-28 at 14:43 +0100, Jean Guyader wrote:
>> On 28/06 01:36, Ian Campbell wrote:
>> > On Thu, 2012-06-28 at 13:10 +0100, Jean Guyader wrote:
>> > > On 28/06 12:58, Ian Campbell wrote:
>> > > > On Thu, 2012-06-28 at 12:43 +0100, Jean Guyader wrote:
>> > > > > On 28/06 12:34, Ian Campbell wrote:
>> > > > > > On Thu, 2012-06-28 at 11:38 +0100, Jean Guyader wrote:
>> > > > > > > On 26/06 03:38, Ian Campbell wrote:
>> > > > > > > > Hi,
>> > > > > > > >
>> > > > > > > > Sorry it's taken me so long to get round to responding to this.
>> > > > > > > >
>> > > > > > > > On Mon, 2012-06-25 at 10:05 +0100, Tim Deegan wrote:
>> > > > > > > > > At 22:14 +0100 on 14 Jun (1339712061), Jean Guyader wrote:
>> > > > > > > > > > On 14 June 2012 16:35, Tim Deegan <tim@xxxxxxx> wrote:
>> > > > > > > > > > > At 16:10 +0100 on 14 Jun (1339690244), Jean Guyader 
>> > > > > > > > > > > wrote:
>> > > > > > > > > > >> On 14/06 03:56, Tim Deegan wrote:
>> > > > > > > > > > >> > At 11:55 +0100 on 14 Jun (1339674908), Jean Guyader 
>> > > > > > > > > > >> > wrote:
>> > > > > > > > > > >> > > Are you talking about having different version of 
>> > > > > > > > > > >> > > V4V driver running
>> > > > > > > > > > >> > > in the same VM?
>> > > > > > > > > > >> >
>> > > > > > > > > > >> > Yes.
>> > > > > > > > > > >> >
>> > > > > > > > > > >> > > I don't think that is a problem they both interact 
>> > > > > > > > > > >> > > with Xen via
>> > > > > > > > > > >> > > hypercall directly so if they follow the v4v 
>> > > > > > > > > > >> > > hypercall interface it's
>> > > > > > > > > > >> > > all fine.
>> > > > > > > > > > >> >
>> > > > > > > > > > >> > AFAICS if they both try to register the same port 
>> > > > > > > > > > >> > then one of them will
>> > > > > > > > > > >> > silently get its ring discarded.  And if they both 
>> > > > > > > > > > >> > try to communicate
>> > > > > > > > > > >> > with the same remote port their entries on the 
>> > > > > > > > > > >> > pending lists will get
>> > > > > > > > > > >> > merged (which is probably not too bad).  I think the 
>> > > > > > > > > > >> > possibility for
>> > > > > > > > > > >> > confusion depends on how you use the service.  Still, 
>> > > > > > > > > > >> > it seems better
>> > > > > > > > > > >> > than the xenstore case, anyway. :)
>> > > > > > > > > > >> >
>> > > > > > > > > > >>
>> > > > > > > > > > >> Not silently, register_ring will return an error.
>> > > > > > > > > > >
>> > > > > > > > > > > Will it?  It looks to me like v4v_ring_add just clobbers 
>> > > > > > > > > > > the old MFN
>> > > > > > > > > > > list.
>> > > > > > > > > > >
>> > > > > > > > > >
>> > > > > > > > > > Ha yes. It does that now but I think it should return an 
>> > > > > > > > > > error
>> > > > > > > > > > informing up the stack that a ring has already been 
>> > > > > > > > > > registered.
>> > > > > > > > >
>> > > > > > > > > Actually, I think it's deliberate, to allow a guest to 
>> > > > > > > > > re-register all
>> > > > > > > > > its rings after a suspend/resume or migration, without 
>> > > > > > > > > having to worry
>> > > > > > > > > about whether it was actually migrated into a new domain or 
>> > > > > > > > > not.
>> > > > > > > >
>> > > > > > > > Which takes us back to the original issue Tim asked about with
>> > > > > > > > cohabitation of multiple (perhaps just plain buggy or even 
>> > > > > > > > malicious)
>> > > > > > > > v4v clients in a single domain, doesn't it?
>> > > > > > > >
>> > > > > > >
>> > > > > > > There is nothing wrong the two v4v driver running in the same 
>> > > > > > > guest.
>> > > > > > > The probably that Tim reported was about trying to create two 
>> > > > > > > connections
>> > > > > > > on the same port. Today with the code that I've submited in the 
>> > > > > > > RFC
>> > > > > > > one will overwrite the other silently which isn't a good thing, 
>> > > > > > > that can
>> > > > > > > easily be changed to notify which one got registered up the 
>> > > > > > > stack.
>> > > > > >
>> > > > > > So they'd somehow need to randomise (and retry) their use of source
>> > > > > > ports in order to co-exist?
>> > > > > >
>> > > > >
>> > > > > That can be assimilated to two userspace programs trying to bind to 
>> > > > > the
>> > > > > same TCP port. I think it's not v4v's responsability to solve this 
>> > > > > problem.
>> > > >
>> > > > An application using TCP doesn't need to worry about choosing its own
>> > > > source port though.
>> > > >
>> > > > Or does this only effect destination / listening ports?
>> > > >
>> > >
>> > > The guest v4v driver knows which port are in used so if you put port 0
>> > > we will pick a random unused number for the source port.
>> >
>> > Except when there are two such drivers each doesn't know which the other
>> > one is using.
>> >
>>
>> Then the kernel will try to register the ring and the hypercall will fail
>> because it's already registered.
>
> At which point what happens? How do two unrelated V4V drivers co-exist
> given this?
>

It happens when both driver will start registering their rings and if they are
using the same port. One will get a success out of the hypercall the other one
a failure. If we are in the case that user space used 0 for port we
will retry with
another random port number until it succeed.

Jean

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