[Xen-users] How to create a domU on RedHat Enterprise AS 4.4?

["Liang Yang" <multisyncfe991@xxxxxxxxxxx>]

Hi,

I installed Xen 3.0.2 on RedHat Enterprise AS 4.4. Now I try to create domU 
from dom0. I copied the whole filesystem of a RedHat to the logic volume 
group (/dev/VG_Dom6_Linux/LogVol00) I created for domU.  I then start the 
domU kernel, however I got the following errors:
*****************Message when booting domU kernel***************************
..
..
..
INIT: version 2.85 booting
               Welcome to Red Hat Enterprise Linux AS
               Press 'I' to enter interactive startup.
Starting udev:  [  OK  ]
Initializing hardware...  storage network audio done[  OK  ]
raidautorun: failed to open /dev/md0: 6
Configuring kernel parameters:  [  OK  ]
Setting clock  (localtime): Fri Sep  8 19:41:07 MST 2006 [  OK  ]
Setting hostname localhost.localdomain:  [  OK  ]
Checking root filesystem
[/sbin/fsck.ext3 (1) -- /] fsck.ext3 -a /dev/VG_Dom6_Linux/LogVol00
fsck.ext3: /dev/VG_Dom6_Linux/LogVol00:
The superblock could not be read or does not describe a correct ext2
filesystem.  If the device is valid and it really contains an ext2
filesystem (and not swap or ufs or something else), then the superblock
is corrupt, and you might try running e2fsck with an alternate superblock:
   e2fsck -b 8193 <device>

No such file or directory while trying to open /dev/VG_Dom6_Linux/LogVol00
[FAILED]

*** An error occurred during the file system check.
*** Dropping you to a shell; the system will reboot
*** when you leave the shell.
Give root password for maintenance
(or type Control-D to continue):
Login incorrect.
Give root password for maintenance
(or type Control-D to continue):


Here is the content of my domU config file:
kernel = "/boot/vmlinuz-2.6-xenU"
ramdisk = "/boot/initrd-2.6-xen.img"
memory = 512
name = "domain1"
extra = "3"
vif = [ 'bridge=xenbr0' ]
dhcp = "dhcp"
disk = ['phy:/dev/VG_Dom6_Linux/LogVol00,sda1,w' ]
root = "/dev/sda1 ro"


Could anyone help me this? I got stuck for this issue for two days.

Thanks,

Liang




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